No it's not stupid it's a good question to ask.
Firstly for conservative systems (such as a lightwave) the intensity (measured by the wave amplitude) diminishes as the wave gets further from the source.
This is a straightforward consequence of the law of conservation of energy.
Consider a sphere or ball of radius r centrered the source.
The wave(s) start of with total energy E joules flowing (transported) per second.
Now this total energy E moves away from the source every second and passes through a sphere of radius r every second. If it did not do this there would be a build up of energy on the sphere.
Thus the surface energy flux is E divided by the surface area of the sphere. That is E/4∏r
2
Clearly this same energy must pass through a sphere of radius 2r and surface energy E / 4∏(2r)
2
So the energy density diminishes in inverse relation to the square of the distance.
However we are not interested in the energy density directly, but the sound amplitude.
Look here at the inverse square law and in particular at the acoustic example
http://en.wikipedia.org/wiki/Inverse-square_law#Example_2
Note that the energy is proportional to the amplitude squared.
When you have digested that you have understood why, even in conservative systems, the energy spreads out with distance we can address non conservative systems.
Here you must add in terms for
1) Dissipation eg as heat or against friction. Energy here is removed faster than the inverse sq law and converted to something other form.
2) Dispersion.
All the foregoing assumes a linear response by the medium to displacement. That is the restoring force that produces the (simple) harmonic motion of each oscillator in the wave is proportional to the displacement.
If the response in non linear we have additional terms which reduce the amplitude (but not the energy since this is conserved).