KWhat conditions must a wavefunction satisfy for all values of x?

In summary, the conditions a well behaved wavefunction (phi) must satisfy for all x are that it should be continuous and finite everywhere, and that its first derivative should also be continuous and finite everywhere. These constraints are based on the physical justification that a wave function blowing up at infinity is not desirable and that the modulus squared of the wave function represents a probability distribution, making it important for the function to be consistent at different points. The rule for a continuous first derivative also stems from a similar concept related to momentum.
  • #1
r-dizzel
10
0
hey all!
does anyone know the conditions a well behaved wavefunction (phi) must satisfy for all x? and any physical justifications for them?

is it something to do with continuity at boundaries? or to do with the differential of the wavefunction?

cheers for any input

roc
 
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  • #2
r-dizzel said:
hey all!
does anyone know the conditions a well behaved wavefunction (phi) must satisfy for all x? and any physical justifications for them?

is it something to do with continuity at boundaries? or to do with the differential of the wavefunction?

cheers for any input

roc

In QM a well behaved function is generally a function that is continuous and finite everywhere, and whose first derivative is continuous and finite everywhere also.
 
  • #4
cheers for the help gents!
 
  • #5
as far as the physical justification for the constraints, are there any?
 
  • #6
cristo said:
In QM a well behaved function is generally a function that is continuous and finite everywhere, and whose first derivative is continuous and finite everywhere also.

agreed... well defined,,


anything else?
 
Last edited:
  • #7
r-dizzel said:
as far as the physical justification for the constraints, are there any?


A wave function blowing up at infinity isn't really a good thing is it?
 
  • #8
say_physics04 said:
agreed... well defined,,


anything else?

Erm... I'm not sure I know what you're getting at!
 
  • #9
r-dizzel said:
as far as the physical justification for the constraints, are there any?

The modulus squared of the wave function is a probability distribution. Is there any physical reason to say that at the point [tex]x = 0 + \epsilon [/tex] there's one probability density, and then at [tex]x = 0 - \epsilon[/tex] it's wildly different?

Also, the continuous first derivative rule comes from a similar notion with regards to the momentum. I'll leave it to you to figure that one out.
 

1. What is a wavefunction?

A wavefunction is a mathematical function that describes the quantum state of a particle or system. It contains information about the position, momentum, energy, and other properties of the system.

2. What are the conditions for a valid wavefunction?

The wavefunction must be continuous, single-valued, and finite everywhere. It must also be square-integrable, meaning that its amplitude squared must be integrable over all space.

3. What is the significance of the normalization condition for a wavefunction?

The normalization condition ensures that the total probability of finding a particle in any region of space is equal to 1. This is necessary for the wavefunction to accurately describe the behavior of the particle.

4. Can the wavefunction be complex?

Yes, the wavefunction can be complex, as it is a mathematical representation of a quantum state. However, the probability of finding a particle in a certain state is determined by the square of the wavefunction, which is always a real value.

5. How does the wavefunction evolve over time?

The wavefunction evolves over time according to the Schrödinger equation, which describes the time-dependent behavior of quantum systems. This evolution is deterministic, meaning that the future state of the system can be predicted from its current wavefunction.

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