Wavelength of a wave in a closed tube

In summary, in a lab experiment, a closed tube with piezo electric transducers was attached to a frequency generator to find the frequencies that caused resonance. The lab wants to calculate the velocity of the wave using data and states that there are antinode pressure waves at both ends, making the length of the tube equal to one wavelength at the lowest frequency. However, there may be half a wavelength between the antinodes. It is unclear if the tube was closed or open at both ends, which would affect the length of the tube for the different resonant modes. The number of waves inside the tube increases by either 1/2 or a whole when another resonant frequency is reached. Further clarification is needed on the set-up of the
  • #1
warfreak131
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Homework Statement



In a lab that we performed, we had a closed tube with piezo electric transducers on both ends, and they were attached to a frequency generator. We found the frequencies that caused resonance, and the lab wants us to calculate the velocity of the wave using data. The lab says that there are antinode pressure waves at both ends, and therefore, the length of the tube is equal to one wavelength at the lowest frequency.

But at the lowest frequency, wouldn't one antinode to the next correspond to half a wavelength? The two anti nodes in question would be one antinode with max positive displacement to one with the max negative displacement.
 
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  • #2
You are right, there is half wavelength distance between the antinodes. But it could be that those transducers generated in-phase pressure changes, then there was one wavelength between the ends.

ehild
 
  • #3
so should i go with my gut and say half wavelength or trust the manual to be right?

also, assuming its a full wavelength, it asks us to find the velocity at higher resonant frequencies. so would the number of waves inside the tube increase by 1/2 or by a whole when another resonant frequency is reached?
 
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  • #4
I am confused about the set-up of the experiment. Was that tube exited at one end and closed at the other end where the pressure was measured? The pressure can have antinode at a closed end, but than the length of the tube is L=((2n+1)/4) λ with n=0, 1, 2, 3, ... If the tube was either closed or open at both ends it was a half wave between the ends in case of the fundamental frequency. In case of the other resonant modes, the length of the tube is integer multiple of the half wavelength: L=n(λ/2).

See http://en.wikipedia.org/wiki/Acoustic_resonance#Cylindersehild
 
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  • #5


I would like to clarify that in a closed tube, the wavelength of a wave is equal to twice the length of the tube. This is because in a closed tube, there are two points of maximum displacement (antinodes) at each end. The distance between these two points is equal to half a wavelength. Therefore, in order to calculate the wavelength of the wave, we would need to multiply the length of the tube by 2.

Furthermore, the frequency at which resonance occurs in a closed tube is determined by the length of the tube and the speed of the wave. Therefore, we can use the formula v = fλ to calculate the velocity of the wave, where v is the velocity, f is the frequency, and λ is the wavelength.

In this case, since the length of the tube is equal to one wavelength at the lowest frequency, we can simply use the lowest frequency and the length of the tube to calculate the velocity. However, it is important to note that the wavelength will change at different frequencies, so it is best to take multiple measurements and use an average to calculate the velocity accurately.

In conclusion, the wavelength of a wave in a closed tube is equal to twice the length of the tube and can be used to calculate the velocity of the wave using the formula v = fλ. It is important to take multiple measurements and use an average to ensure accurate results.
 

1. What is the meaning of "wavelength of a wave"?

The wavelength of a wave is the distance between two consecutive points on a wave that are in phase, or have the same position and direction of motion. In other words, it is the length of one complete cycle of a wave.

2. How is wavelength measured in a closed tube?

In a closed tube, the wavelength of a wave is determined by the length of the tube. This is because a closed tube creates standing waves, where the ends of the tube act as nodes (points of no displacement) and the middle of the tube acts as an antinode (point of maximum displacement).

3. What is the relationship between wavelength and frequency in a closed tube?

The relationship between wavelength and frequency in a closed tube is inverse. This means that as the wavelength increases, the frequency decreases and vice versa. This relationship is described by the formula: wavelength = 4L/n, where L is the length of the tube and n is the harmonic number.

4. How does the shape of a closed tube affect the wavelength of a wave?

The shape of a closed tube does not affect the wavelength of a wave, as long as the length of the tube remains constant. This is because the length of the tube is the determining factor in the wavelength of a wave in a closed tube.

5. Can the wavelength of a wave in a closed tube be changed?

Yes, the wavelength of a wave in a closed tube can be changed by altering the length of the tube. This can be done by physically changing the length of the tube or by changing the frequency of the wave. However, the wavelength can only take on specific values based on the length of the tube and the harmonic number, and cannot be changed arbitrarily.

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