Wavelength of bullet and proton, same momentum

AI Thread Summary
A question was raised about the wavelengths of a bullet and a proton that have the same momentum. The de Broglie wavelength formula, which states that wavelength equals Planck's constant divided by momentum, was referenced. Since both the bullet and proton share the same momentum, they consequently have the same wavelength. The discussion confirmed that the wavelengths are indeed equal. This highlights the application of de Broglie's principle in understanding wave-particle duality.
Cataklyzm
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Hi.

There's this question that was posed.
And I'm totally lost.:redface: If my professor explained how it's all derived it would've been useful.
Here we are:

A bullet and a proton have the same momentum. Which has the longer wavelength?

Any help?
Thanks,
Cataklyzm
 
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Tell me what you know about the de Broglie wavelength.
 
Ahh.. de Broglie's.. wavelength = h / momentum..
Because h is Planck's constant.. and momentum is constant in this example.
wavelength is constant.. So they both have the same wavelength.

Thanks.
 
Cataklyzm said:
So they both have the same wavelength.
Thanks.
Glad to be of service :smile:
 
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