Waves and A Fisherman on a boat

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The wave equation describes a water wave traveling on a lake, and the time for one complete wave pattern to pass a stationary fisherman is calculated using the formula 2π/5.4, resulting in approximately 1.16 seconds. The horizontal distance traveled by the wave crest during this time involves determining the wavelength, which is calculated as 2π divided by the wave number (0.0045 m^-1), yielding a wavelength of approximately 1396.263 meters. It is clarified that the wave number is not the speed of the wave, and the relationship between time and wavelength is confirmed as intuitive. The calculations align correctly with the physics of wave motion. The discussion emphasizes understanding the relationship between wave properties and their implications for a stationary observer.
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a water wave is traveling in a straight line on a lake is described by the equation
y(x,t)=.0375mcos(.0045 m^-1 (x) + 5.4 s^-1 (t))

How much time does it take for one complete wave pattern to go past a fisherman in a boat at anchor, and what is the horizontal distance does the wave crest travel in that time.

My question is about the second part of the question.

for the first part I got 2Pi/5.4=t

so for the horizontal distance is it just .0045*((2Pi)/5.4)
 
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No, because 0.0045 m^-1 isn't the speed of the wave (and it doesn't have the right units).

0.0045 m^-1 is k and wavelength is 2*pi/k. Is it intuitive that one wavelength passes the fisherman in the time it takes a complete cycle to go past?
 
So was my time right?

so if lambda = 2*pi/k

would that mean the distance would be 1396.263?
 
Yes.
 
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