What Is the Maximum Length of a Plasma Tube to Excite Only One Frequency?

AI Thread Summary
The discussion revolves around determining the maximum length of a plasma tube that can excite only one frequency of light, specifically at 5E14 Hz with a spectral width of ±1E9 Hz. The key equations involved are the relationship between wavelength and tube length (λ = 2L/n) and the speed of light (c = λν). To ensure that only one frequency propagates, the wavelength must be unique enough to avoid harmonics of other frequencies. The challenge lies in mathematically setting up the problem to account for the spectral width and the resonant conditions of the optical cavity. Understanding these principles is crucial for solving the problem effectively.
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Homework Statement



Alright this is from the MIT intro series book by AP French on Waves and Optics, Problem 6-10 (If you happen to have the book)

"A laser can be made by placing a plasma tube in an optical presonany caity formed by two highly reflecting faltmirrors, which act like rigid walls for light waves. The purpose of the plasma tube is produce light by exciting normal modes of the cavity."

"Supose that the plasma tube emits light centered at frequency 5E14 Hz and that it has a spectral width of +- 1E9 Hz. What is the largest value of the Length of the Tube (L) where only one frequency in the spectrum will be excitied in the plasma tube? Assume the speed of light to be c=3E8 m/s"

Any help on this would be great, I have no idea how to do it.



Homework Equations



\lambda=2L/n

c=\lambda*\nu

The Attempt at a Solution



So, we know that this wavelength has to be completely unique, and so tiny that no other wave can propigate. This means that we need to find the largest wavelength whose fundamental isn't not a harmonic of any other frequencies, which would allow those frequencies to propigate in the tube.

I ahve no clue how to set this up mathematically
 
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Here's my guess at a starting point:
Lasers work because of the resonant cavity. For a cavity with mirrors at either end, a resonant wavelength is one such that after making a round trip in the cavity, there's some multiple of 2pi phase shift. (That's where your \lambda = 2L/n comes from, right? The n there is an integer, not refractive index) So you can also say that the cavity length L = n*lambda/2, and then consider how big n can be before another lambda is also satisfied. This is probably where the spectral width comes in.
 
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