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Weight at an Angle

  1. Sep 30, 2013 #1
    1. The problem statement, all variables and given/known data
    "You are a 115-kg football player. You go stand on your bathroom scale, but the scale is not perfectly horizontal. It is instead inclined at an angle of 40° from the vertical (which makes it rather hard to stand on, but whatever). The scale is screwed into the floor so it doesn’t slip. The scale is a “proper” physical scale, with the reading in Newtons. What is your weight according to the reading on the scale?"

    3. The attempt at a solution
    I thought that since the angle from the vertical was 40 degrees, the angle from the horizontal ground would be 55 degrees. Then, I used mgcos55 to try and find the weight on Newtons, as the angle from the horizontal ground fits into this equation. However, my answer was wrong. What is it that I'm doing wrong?
     
  2. jcsd
  3. Sep 30, 2013 #2
    90 - 40 = 50. Not 55.
     
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