Weight before/after change in rotation Speed

Charanjit
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Homework Statement



How would the weight of a person in some place (48 North and 123 West) change if the rotation rate increased so a day was 3 hours long?


Homework Equations



F=ma

The Attempt at a Solution



The above is not the only equation I think that is needed for this. Not sure about this, but coriolis force maybe needed. I just have no clue about this.
 
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Sum of forces on the person = 0 since he's not going anywhere (hint: there are 3 terms in the equation, and yes, it's basically F = ma, except if you're going to derive evbrything you need from that one equation, remember that F and a are vectors, not just scalars).
 
Yes, I understand that F=ma = 0 since the person will not move. Now the three terms that come into play... would the centrifugal force help at all since the Earth is rotating?
 
Yes it would. Since gravitational attrcation is constant, irrespective of rotational speed, what force do you think has to change so the three add up to zero?
 
You are working in a frame fixed to the Earth which is a rotating object hence you are in a rotating frame. Which means that you need to use fictious forces. You need the centrifugal force. The coriolis force is tangent to the Earth's surface... Calculate the component of the centrifugal force normal to the surface of the earth...
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
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