Weight of system: water container and rock

AI Thread Summary
In the discussion, two scenarios involving a water container and a rock are analyzed regarding their weight readings on a scale. In the first case, when the rock is placed on the closed lid, the scale reads the same weight as when the rock is submerged in the water, as buoyant forces are internal to the system. However, when the rock is suspended under the water's surface using a force meter, the scale reading decreases due to the buoyancy force acting on the rock. This demonstrates that the weight of the system changes when the rock is not resting on the bottom. The conversation highlights the importance of understanding buoyancy in relation to weight measurements.
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Homework Statement



Container filled with water is placed on a scale.

case #1 Lid is closed. Rock is placed on top of the lid.

case #2 Rock is placed inside the water container, it sinks to bottom. Lid is closed.

How does the weight (reading on the scale) compare in the two cases?

Homework Equations



The Attempt at a Solution



I think the weight is the same in the two cases.

But I have done some tricky questions involving buoyancy/weight.water level, and sometimes the answer is not so simple. Once I can confirm this answer, I will post some variants of this situation and try to see where my confusion is.
 
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physickkksss said:
I think the weight is the same in the two cases.
You are correct. Any buoyant forces acting on the rock when submerged are internal to the system and will not affect its scale weight.
 

Homework Statement



Now what if the rock is suspended from a force meter, so that it is under the surface of the water but not on the bottom

(and the string from the force meter goes through a small hole in the lid, so that mass is still there)

Homework Equations



The Attempt at a Solution



I think here the weight of the system becomes

W = (Weight of water & container) + Buoyancy force on rock

So the weight on the scale should be less than the two cases before
 
physickkksss said:
I think here the weight of the system becomes

W = (Weight of water & container) + Buoyancy force on rock

So the weight on the scale should be less than the two cases before
You are correct.
 
You are correct and this is easy to demonstrate using kitchen scales ( electronic is best)
And a force meter. If you lower the stone into the water you will see the force meter reading decrease and the scales reading increase as you described
 
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