Weight & Tension Helo 2 Tension

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To find the weight in the statics problem, the equations for the sum of forces in both the X and Y directions are critical. The tension T1 is resolved into components, leading to the equations ΣFx = 480 cos(30) - 450 = 0 and ΣFy = 480 sin(30) - W = 0. The calculated weight W is approximately 240 lb, derived from the vertical force balance. Additionally, understanding the critical constraints of the tensions is essential, as the weakest link in the system will determine the maximum weight supported. The relationship between T1 and the weight indicates that the weight supported is half of T1.
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Homework Statement



How to find Weight in this problem?
I am trying to do this statics problem
but I don't know how to find the weight
so I can solve for
Sum Fy = 0
here is the picture link
vwu4y0.jpg


Homework Equations


TI
sum of Fx = 0
480 cos(30) - 450 = 0
-34

T1
sum of Fy = 0
480 sin(30) - W = 0
how do I find the weight to substract it

The Attempt at a Solution



I don't know I am like really stuck
 
Last edited:
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Resolve the tensions into their X and Y components.

The system is static, so the sum of the X forces must equal 0 and sum of the Y as well.

Be careful. One of the tensions may not be critical to holding up the weight.
 
wht the equation I wrote is not right?
Sum of the Force in X = 480 cos(30) - 450 = 0
I get = 415 - 450
= -34
Sum of the Force in y = 480 sin (30) - W = 0
240 -w = 0

I how do I solve for weight
the answer is about 259.81 lb
& there is also for t2


ΣFx = 0; 480cos(30) − 450 = 0

ΣFy = 0; 480sin(30) − W = 0

(F ab2 W2) = Find (FAB W)

W2 = 240.00 lb
W= min (W1 W2) = W 240.00 lb
 
You have 2 tensions to worry about.

Like the weakest link - that's where it will break right?

First figure out which is the critical constraint.

If T1 = 450 max, what does that translate to for the chain that can withstand 480? Will the 450 break if it's 480, or will the 480 break if it's 450?

Then you are armed with what you need to know, because from your equations, you can see that whatever the T1, the weight it can support is 1/2 T1.
 
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