Weinberg's Cosmology: Neglecting (1+z(eq)) in Denominator

[EhsanZ]

In equation below
〖H₁〗^2/〖H₀〗^2 =Ω₀(cri) (R₀⁴)/(R₁⁴(1+z(eq)))

Why is the term “(1+z(eq))” negligible in denominator according to the term “ R₁⁴ ” ?

Weinburg did it in his book named "Cosmology".

 

[JHamm]

I would assume that z is incredibly close to 0.

 

[George Jones]

Weinburg did it in his book named "Cosmology".

I would like to see the context, but I don't feel like looking for this by flipping through Weinberg page-by-page. Could you please give the page number?