Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Weyl Curvature, Mach's Principle, and Heisenberg Uncertainty?

  1. Jul 26, 2004 #1
    I have been reading that the quantity called "Weyl curvature" can exist independently of any matter, or energy, in the universe? :confused:

    This seems to contradict Heisenberg uncertainty which says there can be no 100% vacuum, because uncertainty in position and uncertainty in momentum must be greater than zero:

    DxDp >= [Planck's constant]/[2*pi]

    Mach's principle seems to say that the distribution of matter-energy determines the geometry of space-time, and if there is no matter-energy then there is no geometry.

    The Weyl tensor vanishes for a constant curvature if there are no
    tidal forces. So it appears that a Weyl curvature, which is described
    as 1/2 of the Riemann curvature tensor[where it is split into two
    parts, the Ricci tensor and the Weyl tensor] is dependent on
    matter-energy -"existing" in the universe also?



    Thanks for the help.
     
    Last edited: Jul 26, 2004
  2. jcsd
  3. Jul 26, 2004 #2
    Your forgetting about the incompatability between GR and QM
     
  4. Jul 27, 2004 #3
    Thanks yes, classical GR and QM are incompatable, if my interpretation is correct.

    The various GR books, seem to explain that the Weyl tensor Cabcd measures tidal distortion.

    They start with the 256 = 4^4 component tensor Rabcd, and then impose the symmetries required by curvature Rabcd = R[ab][cd] = R[cd][ab] and
    R[abcd] = 0 and Ra[bcd] = 0

    Then the Riemann curvature tensor Rabcd has 20 independent components.

    Decompose Rabcd into the 10-component symmetric Ricci tensor Rab and the 10-component conformal traceless Weyl tensor Cabcd. Then the Einstein tensor Gab is given by Gab = R_ab - (1/2)R, where R is the scalar curvature?

    The Riemann curvature tensor Rabcd obeys the Bianchi identities, and the Einstein tensor Gab is the only contraction that obeys contracted Bianchi identities, which mean from a geometric perspective, that Eli Cartan's boundary of a boundary is zero?

    It seems to me that a universe devoid of matter would have energy distortions allowing for uncertainty, giving a tidal distortion[gravity waves? quantum foams?] and hence, a non-zero Weyl tensor?
     
    Last edited: Jul 27, 2004
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Weyl Curvature, Mach's Principle, and Heisenberg Uncertainty?
  1. Mach's principle (Replies: 58)

  2. Mach's principle (Replies: 7)

  3. Mach's principle (Replies: 42)

  4. Mach principle (Replies: 3)

  5. Mach's principle (Replies: 1)

Loading...