Weyl Curvature, Mach's Principle, and Heisenberg Uncertainty?

Click For Summary
SUMMARY

The discussion centers on the relationship between Weyl curvature, Mach's Principle, and Heisenberg Uncertainty. It establishes that Weyl curvature can exist independently of matter or energy, which contradicts Heisenberg's principle that asserts a vacuum cannot be completely devoid of energy. The conversation highlights that the Weyl tensor, a component of the Riemann curvature tensor, measures tidal distortion and is influenced by the distribution of matter-energy in the universe. The participants conclude that a universe without matter may still exhibit energy distortions, leading to a non-zero Weyl tensor.

PREREQUISITES
  • Understanding of General Relativity (GR) principles
  • Familiarity with Quantum Mechanics (QM) concepts
  • Knowledge of Riemann curvature tensor and its components
  • Basic grasp of Mach's Principle and its implications
NEXT STEPS
  • Study the implications of the Weyl tensor in General Relativity
  • Explore the relationship between Mach's Principle and gravitational theories
  • Investigate the compatibility issues between General Relativity and Quantum Mechanics
  • Learn about the Bianchi identities and their significance in curvature tensors
USEFUL FOR

Physicists, cosmologists, and students of theoretical physics interested in the interplay between gravity, quantum mechanics, and the geometric structure of spacetime.

PFanalog57
Messages
384
Reaction score
0
I have been reading that the quantity called "Weyl curvature" can exist independently of any matter, or energy, in the universe? :confused:

This seems to contradict Heisenberg uncertainty which says there can be no 100% vacuum, because uncertainty in position and uncertainty in momentum must be greater than zero:

DxDp >= [Planck's constant]/[2*pi]

Mach's principle seems to say that the distribution of matter-energy determines the geometry of space-time, and if there is no matter-energy then there is no geometry.

The Weyl tensor vanishes for a constant curvature if there are no
tidal forces. So it appears that a Weyl curvature, which is described
as 1/2 of the Riemann curvature tensor[where it is split into two
parts, the Ricci tensor and the Weyl tensor] is dependent on
matter-energy -"existing" in the universe also?



Thanks for the help.
 
Last edited:
Physics news on Phys.org
Your forgetting about the incompatability between GR and QM
 
keebs said:
Your forgetting about the incompatability between GR and QM

Thanks yes, classical GR and QM are incompatable, if my interpretation is correct.

The various GR books, seem to explain that the Weyl tensor Cabcd measures tidal distortion.

They start with the 256 = 4^4 component tensor Rabcd, and then impose the symmetries required by curvature Rabcd = R[ab][cd] = R[cd][ab] and
R[abcd] = 0 and Ra[bcd] = 0

Then the Riemann curvature tensor Rabcd has 20 independent components.

Decompose Rabcd into the 10-component symmetric Ricci tensor Rab and the 10-component conformal traceless Weyl tensor Cabcd. Then the Einstein tensor Gab is given by Gab = R_ab - (1/2)R, where R is the scalar curvature?

The Riemann curvature tensor Rabcd obeys the Bianchi identities, and the Einstein tensor Gab is the only contraction that obeys contracted Bianchi identities, which mean from a geometric perspective, that Eli Cartan's boundary of a boundary is zero?

It seems to me that a universe devoid of matter would have energy distortions allowing for uncertainty, giving a tidal distortion[gravity waves? quantum foams?] and hence, a non-zero Weyl tensor?
 
Last edited:

Similar threads

  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 23 ·
Replies
23
Views
7K
  • · Replies 4 ·
Replies
4
Views
5K