What algebraic property can I use here?

AI Thread Summary
The discussion revolves around solving the equation 5 = [(x)(4+x)] / (4-x) and finding the value of x without using the quadratic formula. Participants clarify that multiplying by the reciprocal requires balancing both sides of the equation, and they emphasize the importance of applying basic algebraic properties, such as adding or multiplying the same quantity to both sides. There is confusion regarding the solution x = 5, with one participant suggesting that it may not be the only solution, as the equation can yield two other values. Ultimately, the conversation highlights the need for a clear understanding of algebraic techniques to solve equations effectively.
megaboy123

Homework Statement


[/B]
example problem: 5 = [(x)(4+x)] / (4-x)

answer: 5

Homework Equations


Unsure what to use.

3. The Attempt at a Solution

Not sure what my professor did, but I thought that if i multiply by the reciprocal of something, I have to balance by multiplying the other side as well. It seems like everything just canceled out and the only thing left was x = 5. I would just like to know what algebraic property or technique can be used to find x BESIDES quadratic formula.
 
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megaboy123 said:
Not sure what my professor did,...
This is the purpose of taking notes in class.
... but I thought that if i multiply by the reciprocal of something, I have to balance by multiplying the other side as well.
Yes.
It seems like everything just canceled out and the only thing left was x = 5.
Do you mean that is your vague recollection of what the prof did or that is what happened when you did it?
I would just like to know what algebraic property or technique can be used to find x BESIDES quadratic formula.
...what's wrong with the usual rules for multiplication and addition?
What was the topic of the class?

Have you tried substituting the stated solution x=5 into the equation to see if it really is the solution?
(I am guessing that "answer:5 means x=5 will make the expression true...)
 
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its for a general chemistry class, everything makes sense (as far as chemistry goes) up until that last step right before the answer. Not sure what you mean by rules for multiplication and addition.
 
I am guessing that "answer:5" means that putting x=5 into the expression 5=[x(4+x)]/(4-x) will make it true.
Have you tried this to see?

Not sure what you mean by rules for multiplication and addition.
Do you know how to add and how to multiply?
 
megaboy123 said:
Not sure what you mean by rules for multiplication and addition.
If you add the same quantity to both sides of an equation, the new equation will have the same solutions as the original equation.
If you multiply both sides of an equation by the same nonzero quantity, the new equation will have the same solutions as the original equation.
 
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megaboy123 said:

Homework Statement


[/B]
example problem: 5 = [(x)(4+x)] / (4-x)

answer: 5

Homework Equations


Unsure what to use.

3. The Attempt at a Solution

Not sure what my professor did, but I thought that if i multiply by the reciprocal of something, I have to balance by multiplying the other side as well. It seems like everything just canceled out and the only thing left was x = 5. I would just like to know what algebraic property or technique can be used to find x BESIDES quadratic formula.

Are you solving an equation of the form
$$
\frac{x(4+x)}{4-x} = 5 ?
$$
If so, x=5 has nothing to do with it: there are two solutions, which are obtainable from the quadratic solution formula: x ≈ -10.84 and x ≈ 1.84.
 
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