What are the concentrations of HA and A- at this point in concentration?

AI Thread Summary
To determine the concentrations of HA (the weak monoprotic acid) and A- (its conjugate base) after titration, start by calculating the initial concentration of the acid using the formula c = n/v, where n is the moles of acid and v is the volume in liters. After titrating with 10.0 mL of 0.0633 M NaOH, the moles of NaOH added can be calculated, which will neutralize an equivalent amount of HA. The remaining concentration of HA and the formed concentration of A- can then be derived from the stoichiometry of the reaction. Additionally, the concentration of hydroxide ions can be found using Kw = [H+][OH-], allowing for the determination of H+ concentration and further confirming the concentrations of HA and A-. The calculations will yield the final concentrations of HA and A- in the solution.
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Homework Statement



0.00116 moles of a weak monoprotic acid was dissolved in 25.0 mL in water. This solution was titrated with 10.0 mL of 0.0633 M NaOH. What are the concentrations of HA and A- at this point in concentration?


Homework Equations





The Attempt at a Solution

 
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Complexity said:

Homework Statement



0.00116 moles of a weak monoprotic acid was dissolved in 25.0 mL in water. This solution was titrated with 10.0 mL of 0.0633 M NaOH. What are the concentrations of HA and A- at this point in concentration?


Homework Equations





The Attempt at a Solution


Where do I start?
 
Reaction equation won't hurt.

You have to show your attempts at solving the question to receive help. This is a forum policy.
 
Complexity said:

Homework Statement



0.00116 moles of a weak monoprotic acid was dissolved in 25.0 mL in water. This solution was titrated with 10.0 mL of 0.0633 M NaOH. What are the concentrations of HA and A- at this point in concentration?


Homework Equations





The Attempt at a Solution


Maybe you do it using Kw ...
Find the concentration of the weak acid using c= n/v where c is concentration, n is moles and v is volume...
then find the concentration of base using the same formula... since the base is strong , OH concentration is the same as the base itself.i.e.NaOH ...

Now use,
Kw = [H+] [OH-]
use Kw as 10^-14
and conc of OH u calculated earlier..
find conc of H+ ions...the rest is simple...
 
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