What Are the Correct Units for p in the Equation R=pl/A?

  • Thread starter Thread starter phyuk2
  • Start date Start date
  • Tags Tags
    Units
AI Thread Summary
The equation R = ρl/A is used to determine the resistivity (ρ) of a material. Rearranging the equation gives ρ = RA/l. The units for resistance (R) are ohms, which can be expressed as m²kgS⁻³A⁻². The derived units for resistivity (ρ) are confirmed to be ohm-metre, equivalent to m³kgS⁻³A⁻². Thus, the correct units for resistivity are established as m³kgS⁻³A⁻².
phyuk2
Messages
1
Reaction score
0

Homework Statement



rearrange to make p the subject then work out the units for p

R - resistance or wire
A - area in m2
l - length

Homework Equations



R=pl/A


The Attempt at a Solution



p = AR/l

(m2 x m2kgS-3A-2)/m

Resistance is ohms which is m2kgS-3A-2 I think.

p=m3kgS-3A-2
 
Last edited:
Physics news on Phys.org
Yes, your working is right. The units for resistivity is the ohm.metre or m3kgs-3A-2
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top