What Are the Forces Acting on a Gyroscope and How Can They Be Calculated?

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The discussion focuses on understanding the forces acting on a gyroscope, specifically regarding a video that demonstrates a gyroscopic effect. Key questions include the momentum that prevents the cheese from falling and how to calculate the force required to bring it down while maintaining constant RPM from an electric motor. There is confusion about the omega value in calculations, as it appears to be zero in the video, raising questions about the significant coupling force observed. The user seeks clarification on these concepts but expresses frustration over a lack of responses. Overall, the thread highlights the complexities of gyroscopic physics and the need for further explanation.
dislect
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Hello everyone,

I saw this video in youtube:
And I have some questions, can someone please explain me the forces acting on this gyro? what is the momentum that keeps the cheese from falling, the direction of its action don't add up to me

Also, how could i calculate the force needed to take down the cheese to the ground given that the RPM is constant (electric motor), unlike in the video above?

Thanks a lot,
sharon
 
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Hello again,
i tried using the following website after reading about gyros:
http://www.gyroscopes.org/math.asp
what i don't understand is the omega part, it seems to be zero in the youtube video so how come the coupling force is so big?

thanks
 
no one? realy?
is it like holiday now or something? :-)
 

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