What are the forces exerted on a diving board when a person stands on the tip?

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When a 62 kg person stands on the tip of a diving board, the forces exerted by the supports can be calculated using Newton's laws. The downward force due to the person's weight is 607.62 N, which corresponds to F(B). To find F(A), the torque balance equation must be applied, considering the distances from the supports to the point where the person stands. Additionally, a force balance equation is necessary, as the sum of vertical forces must equal zero due to the absence of translational acceleration. Understanding these principles is crucial for accurately determining the forces acting on the diving board.
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Homework Statement



Calculate the forces F (A) and F (B) that the supports exert on the diving board of the figure when a 62 kg person stands at its tip. Ignore the weight of the board. Assume that x-axis points upward.

Homework Equations



F = ma

The Attempt at a Solution



F (B) = (62 kg)(9.8 m/s^2) = 607.62 N

F (A) = (x kg)(9.8 m/s^2) = ______ N

I'm having trouble as to what to use for the mass. I was thinking 62 kg but it wouldn't make sense for them to be the same if A is farther away.
 

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The only force that is equal to (62 kg)*g is the weight of the person. To solve for the other forces, you need to use the torque balance equation. In other words, use the fact that the sum of torques on the board is 0, since it has no rotational acceleration.

You'll also need to use a force balance equation. The sum of vertical forces on the board should be 0, since it has no translational acceleration.
 
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