What are the forces involved in this physics problem?

AI Thread Summary
The discussion revolves around solving a physics problem involving forces, specifically the calculation of work (W) and the role of tension in strings. Participants express confusion about the equations and concepts, particularly regarding friction and the forces acting on a block. It is suggested that W can be determined using the equation W=mg for the hanging mass, and that the tension in the strings balances at the knot. Clarification is sought on the meaning of certain terms in the equations, and it is emphasized that the problem must remain in equilibrium. Ultimately, a solution of 23.3 is mentioned as the answer found in class.
godzillafan868
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1. What does W=? ?
http://img261.imageshack.us/img261/9795/physicsproblemvs2.jpg



2. Not really too sure, but here are some I know:
Fa=Fb*Cos(Theta)b
Fg=Fa*Sin(Theta)a+Fb*Sin(Theta)b


The Attempt at a Solution


I'm completely clueless... We've never done anything in class with Friction and pulling on something involved in one Problem.

EDIT:
I just found out this was posted in the Wrong Physics section... If a moderator or Admin. could be kind enough to move it that would be great:)
 
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Regardless of what forum the question was posted in the question still isn't very clear. W=mg for whatever m the hanging mass is. The tension T on all of those strings is equal, if they are strings.
 
godzillafan868 said:
1. What does W=? ?
http://img261.imageshack.us/img261/9795/physicsproblemvs2.jpg



2. Not really too sure, but here are some I know:
Fa=Fb*Cos(Theta)b
Fg=Fa*Sin(Theta)a+Fb*Sin(Theta)b


The Attempt at a Solution


I'm completely clueless... We've never done anything in class with Friction and pulling on something involved in one Problem.

EDIT:
I just found out this was posted in the Wrong Physics section... If a moderator or Admin. could be kind enough to move it that would be great:)

The only way I could make sense of the question is if it asks "what is W" if the block on the surface is just about to start sliding". In that case, the friction force on the block on the surface would be \mu_s n where n is the weight of that block which is 80 N. This will also be the tension in the horizontal string.

I can't quite make sense of your equations since I don't know what "Sin(theta)a" means.
But consider the knot where all three strings are connected and impose that the net force along x and along y are both zero. That will give you two equations for two unknowns which are F_a and W.
 
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Dick said:
Regardless of what forum the question was posted in the question still isn't very clear. W=mg for whatever m the hanging mass is. The tension T on all of those strings is equal, if they are strings.

Hi Dick. Why do you say that the tension in all strings is the same?
 
Hi nrqed. Meant to say that the tension forces balance at the knot, not that they are equal.
 
This equation has to remain in equilibrium if that helps, but I just found out the answer today in class and it's 23.3.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
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