What Are the Functions and Circuit Analysis Techniques for Op-Amps?

  • Thread starter Thread starter InuyashaITB
  • Start date Start date
  • Tags Tags
    Op-amp
AI Thread Summary
The discussion focuses on the analysis of an operational amplifier (op-amp) circuit, highlighting its various functions and components. The input stage features a parallel inductor and resistor, which affects gain and frequency response, particularly for fast signals. The middle section is identified as a voltage-to-current converter, utilizing a current balance to integrate charge and adjust voltage input. Additionally, an RL parallel circuit at the output isolates the driver from the load, preventing oscillations at high frequencies while maintaining low output impedance at lower frequencies. The conversation emphasizes the importance of understanding these components for effective circuit analysis.
InuyashaITB
Messages
11
Reaction score
2
Hello again, Physics Forums.
I was studying this op-amp (no its not homework) and I am not sure if i am analyzing it correctly or not.

test-990_zpsw9suzksm.png


So far that is what I have. I was also wondering what the purpose of these highlighted sections are:
The RL circuits look like filters, but I don't quite understand why?
Also, i understand that the top one is a totem-pole, but I don't really understand what those are

test-990_zpsnyekgsqb.png
 
  • Like
Likes berkeman
Engineering news on Phys.org
The input stage has L in parallel with R. For fast signals the R will “degenerate” the differential pair gain, but the inductors will short circuit the resistors and so reduce the degeneration at low frequencies and DC. The roll-over frequency will be when the reactance of 20uH = 30.1 ohms. 30R1 / ( 2π * 20uH) = 240kHz.

The middle section is a voltage to current converter. The current balance between the collectors of Q24 and the +IN transistor, will integrate charge in the circuit capacitance to change the voltage input to Q26. R13 then produces a larger Q25 collector current proportional to the Q26 base voltage. The use of R12 makes Q24 and Q25 a fast darlington transistor.

The RL parallel circuit on the output isolates the output driver from the output load at high frequencies. That prevents output stage load dependent oscillation. Again, the output impedance is low for low frequencies and rolls over to approach 39 ohms above about f = 39R / ( 2π * 4uH) = 1.5MHz.
 
  • Like
Likes InuyashaITB
Wow, Thank you for giving such a detailed explanation Baluncore.
If I have any questions i'll make sure to ask here :)
 
  • Like
Likes dlgoff
Hi all I have some confusion about piezoelectrical sensors combination. If i have three acoustic piezoelectrical sensors (with same receive sensitivity in dB ref V/1uPa) placed at specific distance, these sensors receive acoustic signal from a sound source placed at far field distance (Plane Wave) and from broadside. I receive output of these sensors through individual preamplifiers, add them through hardware like summer circuit adder or in software after digitization and in this way got an...
I am not an electrical engineering student, but a lowly apprentice electrician. I learn both on the job and also take classes for my apprenticeship. I recently wired my first transformer and I understand that the neutral and ground are bonded together in the transformer or in the service. What I don't understand is, if the neutral is a current carrying conductor, which is then bonded to the ground conductor, why does current only flow back to its source and not on the ground path...
I have recently moved into a new (rather ancient) house and had a few trips of my Residual Current breaker. I dug out my old Socket tester which tell me the three pins are correct. But then the Red warning light tells me my socket(s) fail the loop test. I never had this before but my last house had an overhead supply with no Earth from the company. The tester said "get this checked" and the man said the (high but not ridiculous) earth resistance was acceptable. I stuck a new copper earth...
Back
Top