What are the meter readings in the circuit?

  • Thread starter Thread starter looi76
  • Start date Start date
  • Tags Tags
    Circuit Meter
AI Thread Summary
The discussion focuses on calculating the meter readings in a circuit based on given voltage and resistance values. The user attempts to find the current through three branches using the formula I = V/R, providing specific calculations for each branch. There is confusion regarding the total equivalent resistance of the circuit, particularly questioning the value of 75 ohms and its relevance. The need for clarification on the formula for finding equivalent resistance in parallel circuits is also highlighted. Accurate understanding of these concepts is essential for correct meter readings in the circuit.
looi76
Messages
80
Reaction score
0

Homework Statement


http://img372.imageshack.us/img372/8240/1005200803ki4.png
What are the meter readings in the circuit on the top?

Homework Equations


V = IR

The Attempt at a Solution



I = \frac{V}{R}

A_2 = \frac{12}{\frac{20}{75}} = 45A

A_3 = \frac{12}{\frac{30}{75}} = 30A

A_1 = \frac{12}{75} = 0.16A

Are my answers correct?
 
Last edited by a moderator:
Physics news on Phys.org
I don't think your answers are correct. What is 75? Is it supposed to be total equivalence resistance of the circuit? If so, then that means the equivalent resistance of the resistors in parallel is 25 ohms, which is not right. What is the formula to find equivalent resistance of resistors in parallel?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top