What Are the Methods for Calculating Concentration of a Mass in a Solution?

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The discussion revolves around calculating the concentration of sodium carbonate (Na2CO3) when dissolved in a 100 cubic cm solution. The initial calculation involved determining moles using the formula mass divided by atomic mass, resulting in 5.8g of Na2CO3 yielding 0.005 moles. The concentration was then calculated as 0.0005M. However, this raised concerns about the accuracy of the concentration, as it seemed low. Participants clarified that concentration should be expressed in mol/dm³, and emphasized the importance of converting cubic centimeters to liters before final calculations. The correct approach involves recognizing that 100 cm³ equals 0.1 dm³, leading to a recalculated concentration of 0.05 mol/dm³, not 0.0005 mol/dm³. This highlights the necessity of unit conversion in concentration calculations.
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Hi guys,here is my question. What is the Concentration of Na2CO3 when it dissolves in a solution and forms a volume of 100 cubic cm?

Concentration= moles/volume.
I found moles using mass/atomic mass of Na2+C+03.
Then i used moles/volume to calculate concentration. Correct?
 
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Mass of Na2CO3 is 5.8g
 
So far so good.
 
I found concentration to be 0.0005M. Could you confirm if this is correct?
 
Sounds a bit low to me, can you show your working?
 
Concentration=moles/volume

Moles = mass/atomic mass, 5.8g/Na2C03

So 5.8/106=0.005moles.

Conc=0.05/100=0.0005M. So?
 
What is the definition of M here?
 
M is concentration. There are two ways of writing it,M or mol/dm3
 
OK, so how many dm3 are there in your solution?
 
  • #10
0.0005mol/dm3
 
  • #11
No... what you'd get in your calculations is 0.0005 mol/cm^3. You should change your mL (cm^3) to L (dm^3) before using it.
 
  • #12
sjb-2812 said:
OK, so how many dm3 are there in your solution?

Kelly09 said:
0.0005mol/dm3

sjb asked about volume of the solution, and you have answered giving concentration...

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