What Are the Oxidation Numbers for Each Element in This Reaction?

AI Thread Summary
The discussion focuses on determining the oxidation numbers for elements in the reaction 3Ag2S + 2Al → 6Ag + Al2S3. The oxidation states are clarified, with silver (Ag) initially at +1 and aluminum (Al) at 0, while sulfur (S) is at -2. Participants identify that silver is oxidized as it loses electrons, while aluminum is reduced as it gains electrons. There is a correction regarding the nature of the reaction, emphasizing that it is not a typical tarnishing reaction. The conversation highlights the importance of accurately calculating and understanding oxidation states in chemical reactions.
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Homework Statement



3Ag2 S + 2Al --> 6Ag + Al2 S3
consider the equation for silver tarnishing.
a) state the oxidation number for each element in the reaction.
b)identify the the oxidized reactant and the reduced reactant.




The Attempt at a Solution



Ag2=2 S= -2 Al=0 ---> Ag=-2 Al2=0 S=2

Ag2 loses the electron so it is the oxidized reactant.
S gains the electron so it is the reduced reactant.

am i close to having the right answer?
 
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Not really. This isn't really a silver tarnishing reaction. It is the opposite of a silver tarnishing reaction. Tarnishing involves the reaction of zero valent metal to its oxidized form.

Yes, the sulfur atom in silver sulfide is at an oxidation state of -2. Literally everything else you have written is incorrect.

Try again. You are on the right track.
 
thanks for the reply. chemistry is not my thing... i am trying.
 
If you try, I'll reply.
 
Ag2=1 S=0 Al=1 ---> Ag=-1 Al2=-1 S=0

Ag gains the electron so it is reduced
Al loses the electron so it is oxidized
 
I'll give you a hint: The sulfur (-2) does not change oxidation state during the reaction. It only swaps partners.

What is the oxidation state of aluminum in the reactant side of the equation (...+ 2Al -->)?
 
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