What Are the Two Angles to Fire a Shell to Hit a Target 1000m Away?

Awsom Guy
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Homework Statement


A shell is fired with a muzzle velocity of 350ms/s at a target 1000m away. Calculate two angles at which the shell can be fired .


Homework Equations


I think these equations might help...
v=u+at
s=ut+1/2at^2
v^2=u^2 + 2as
Hope these eqations are right.

The Attempt at a Solution


I thought about maybe this way:
cos(theta)=...
Sorry that is as far as I can go...
Thanks for any help.
 
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Hi Awsom Guy! :smile:

(have a theta: θ and try using the X2 tag just above the Reply box :wink:)

Yes, those three equations will solve any constant acceleration problem.

The trick in this case is to write two lots of equations, one for the horizontal components of velocity (with a = 0), and one for the vertical (with a = -g).

Call the time taken "t", and the launch angle θ, and get two simultaneous equations from which you can eliminate t to find θ. :smile:
 
Ok I will try...
 

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