What did I do wrong in calculating the x-component of net displacement?

  • Thread starter Thread starter Joe91090
  • Start date Start date
AI Thread Summary
The discussion centers on calculating the x-component of a car's net displacement after it travels two segments: 2.14 km in the x direction and 2.58 km at a 71.6-degree angle to the left. The initial approach using the law of cosines was deemed unnecessary, as a right triangle can be formed to simplify the calculation. Participants emphasize the importance of visualizing the problem and correctly identifying the angles involved. The correct method involves adding the x-component of the angled vector to the initial 2.14 km. Ultimately, the net displacement requires careful consideration of both segments' contributions to the x-axis.
Joe91090
Messages
54
Reaction score
0
What did I do Wrong ??

Homework Statement



A car travels 2.14km in the x direction then turns left 71.6 degrees to the original direction and travels an additional distance of 2.58km. calculate the x component of the cars net displacement.

Homework Equations



law of cosines

The Attempt at a Solution



plugged knowns into law of cosines equations got 2.78. what did I do wrong ??
 
Physics news on Phys.org


Draw a picture, you should have a right triangle. There is no need for the law of cosines.
 


Ive drawn several pictures does it just look like a right triangle ?
 


Draw a line downwards from the final position to the x-axis...now do you see the right triangle?
 


is your first movemment to the east ?
 


Yes. Isn't yours?
 


yes then your 71.6 degrees left so does yours look acute or obtuse ?
 


well if your saying its a right angle it must be acute. I am still not sure its a right angle
 
  • #10


so the answer would be the displacement from (0,0) to the tip of the other vector ?
 
  • #11
Last edited by a moderator:
Back
Top