What Does \mathbf{q_\perp} Represent in e^{i \mathbf{q_\perp \cdot x}}?

MadMax
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If I have e^{i \mathbf{q_\perp \cdot x}} what does it mean?Specifically what does the \mathbf{q_\perp} mean?

thanks
 
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It usually means the perpendicular component of q relative to something.
 
Yes that's what I thought. Relative to what though?

Surely it can't mean relative to x because the dot product would imply that the term always = 0 right?
 
How could I guess 'relative to what'? I'd agree it's probably not x.
 
The equation I'm dealing with which contains this term is

\epsilon(\mathbf{r})=\frac{i}{q_z} \int d^2 \mathbf{x} e^{i \mathbf{q_\bot \cdot x}}[\epsilon_2 e^{iq_z[H+h_2(\mathbf{x})]} - \epsilon_1 e^{iq_z h_1(\mathbf{x})}]

I guess it could be perpendicular to r... but what difference would that make? What would it mean?
 
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It's probably perpendicular to the magnetic field intensity vector H.
 
ahh see the H actually stands for height in this equation. :P h_x is a length also and purely a function of x.

But hmm perpendicular to H you say... that actually makes a lot more sense to me than any of the other variables if H were a vector, unfortunately its a mean separation, so that couldn't be it could it? I mean H is measured in a particular direction but... can you use that perpendicular symbol relative to something that's not a vector but measured in a particular dimension?

Cheers
 
well thinking about it this is a 2 D problem using a radial or cartesian coordinate system. The radial dimensions are expressed by r and the cartesian dimensions are expressed by x= x_x + x_z.

Saying that we are dealing with something perpendicular to r makes no sense to me in the context of the system to be honest. Since it has cartesian symmetry but no radial symmetry. Although I could be missing somthing since the equation comes from a Fourier tranformation which I don't actually understand...

(a Fourier transform of the system

\epsilon(i f, r) = \epsilon_2(i f) when H + h_2(x) \leq z < + \infty
\epsilon(i f, r) = 0 when h_1(x) < z < H + h_2(x)
\epsilon(i f, r) = \epsilon_1(i f) when - \infty < z \leq h_1(x)

)


Saying its perpendicular to x is pointless. So I'm inclined to believe its either perpendicular to x_x or x_z. But which I don't know... :/ Nah actually though I bet if I actually understood the Fourier transform I'd understand what that q is perpendicular to :/ Can anyone help please? :(
 
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