Here's the wiki article:
https://en.wikipedia.org/wiki/P-value
DrDu has provided the correct answer. But let me elaborate.
The topic here is "inferential statistics". That is, to test a hypothesis by collecting evidence and judging to what extent and in what way that evidence supports the conclusion.
From the article:
Recent evidence suggests that the microbial community in the human intestine may play an important role in the pathogenesis of obesity. The aim of this study was to assess the differences in the composition of the intestinal microbiota between obese and normal weight Egyptian children and adults.
So, given this hypothesis, they should be able to observe a correlation between certain gut bacteria and obesity.
Let's say that we tested only 2 Egyptians and found this:
Egyptian 1: obese; harbors Firmicutes; likes Star War movies.
Egyptian 2: not obese; does not harbor Firmicutes; does not like Star War Movies.
If we were a bit reckless, we might conclude that both Firmicutes and liking Star War movies results in obesity. But we have only collected data on two Egyptians.
How confident can we be?
The answer comes when you consider the "null hypothesis". In this case, there would be two null hypothesis:
1) There is no correlation between obesity and Firmicutes.
2) There is no correlation between obesity and liking Star War movies.
From there you ask:
How likely is it that I would results this suggestive given these null hypothesis?
The answer is the "p" value. In this case with only 2 Egyptians, it's only about 50/50 so we cannot discount random chance.
The term "statistical significance" is commonly applied to studies that result in p=90%, 95%, 99%. The author reports in this study:
A probability value (p value) less than 0.05 was considered statistically significant.
- so he is looking for p<=.05. That means that there is a 5% chance of getting p=0.05 results from luck. On average, if you performed the experiment 20 times with 20 different groups of people, you would get a p<=0.05 result about once in those 20 times.
So, what the researchers did was to collect information from 79 Egyptians:
Of the 52 obese Egyptians: 45 have Firmicutes, 7 do not.
Of the 27 normal weight Egyptians: 12 have Firmicutes, 15 do not.
Given the data above, you can compute the "p" value - usually with a calculator.
Using this calculator:
http://www.socscistatistics.com/tests/ztest/Default2.aspx
It turns out that the chance that the study results were purely coincidental is p=0.00008 - which is pretty convincing.
For the Bacteroidetes, the stats were 43/52 and 13/27. When I plugged in those numbers, I get p=0.00132 - not the same as their 0.003.
Also: I noticed that at the start of the study they reported 51 obese and 28 normal, but in the statistical calculations, they used 52 obese and 27 normal weight. There may be an explanation for this in the study - but I didn't catch it. I also noted that they defined obese as BMI>30, normal as BMI<25, and overweight as between those value. In the final tally, only obese and normal were considered - no participants we "overweight". But they did not list "overweight" as one of the disqualifiers for participation in the study.