What does the equation represent?

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SUMMARY

The equation ax² + by² = 0 represents different geometric forms based on the signs of coefficients a and b. When both a and b are of the same sign, it describes a degenerate circle or ellipse, resulting in a single point at the origin (0,0). Conversely, if a and b are of opposite signs, it represents a degenerate hyperbola, which manifests as two intersecting lines at the origin. This analysis clarifies the nature of conic sections derived from the equation.

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Homework Statement


What does ax2 + by2 = 0 represent if
1)a and b are of same sign
2)a and b are of opposite sign.


Homework Equations





The Attempt at a Solution



1) I think it represents a point as radius of circle is 0.
2) No idea
 
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Try writing down the equations and putting them in the form y=f(x) taking a and b as 1 for simplicity.

1) You're right, it is a point in that it is a circle with radius 0. But it also has roots containing i so I'm not sure what to actually call it...

x2+y2=0
y2=0-x2
y=sqrt(-x2)
The square root of a negative number is imaginary
y=+ix

2) This one is actually easier when you think about it

x2-y2=0
y2=0+x2
y2=x2
y=+x

You should be able to recognize what that would look like in a graph.
 
The first one would represent the point x=y=0. The second one, a line with y-intercept =0.
 
Another way to look at this is in terms of specific conic sections. If the equation were ax2 + by2 = 1, this would be:
a) a circle if a > 0, b > 0 and a = b.
b) an ellipse if a > 0, b > 0 and a != b
c) a hyperbola if a and b are opposite in sign

For the equation ax2 + by2 = 0, you can think of this as
a) a degenerate circle if a > 0, b > 0 and a = b. I.e., a circle of radius zero, centered at the origin. In other words, a single point.
b) a degenerate ellipse if a > 0, b > 0 and a != b. Also a single point.
c) a degenerate hyperbola if a and b are opposite in sign. I.e., a pair of straight lines that intersect at the origin.
 
Thanks everone!
 

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