What Does the "p" in "1.25p r/s2" Mean?

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The discussion centers on the meaning of "p" in the context of angular acceleration expressed as "1.25p r/s2." Initially, there is confusion about whether "p" could stand for pico or momentum, given the context of a rotating mass. However, it is later clarified that "p" actually represents pi (π), which is consistent with the notation used in other parts of the problem. The user expresses concern that this misunderstanding led to incorrect answers for subsequent questions. Ultimately, the clarification resolves the confusion regarding the notation used in the physics problem.
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I have a question that says "the angular acceleration is 1.25p r/s2." What does the "p" mean?

Thanks.
 
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Could it be pico? It might help to know the context.
 
A small block of mass m = 0.400 kg is attached to a massless rod of length L = 1.00 m and rotated in a vertical circle with uniform angular acceleration 1.25p r/s2. Assume the mass starts from rest at the top of the circle and rotates clockwise.

...the questions follow after that (such as what is the angular speed at 2 sec), but when I answered them without regard to the "p," I got the answers wrong. This makes me think the "p" actually means something, I just don't know what.

Thanks again.
 
Could this be momentum? I don't know why it would be here, but that's the only thing I can think of...

Edit: Sorry about that. I found out it represented pi. I don't know why it was written only with a p in that particular question (since it was written as "pi" throughout the others), but that's how it goes.

Thanks again.
 
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