What Does the Tangent Line at x=0 Reveal About y=sin(x)?

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Homework Help Overview

The problem involves finding the equation of the tangent line to the function y = sin(x) at the point x = 0, and graphing both the tangent line and the sine function over the interval [-π/4, π/4]. Participants are exploring the implications of this tangent line in relation to the function's behavior at that point.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to differentiate the sine function and apply the point-slope form of a line to find the tangent line. Some participants question the correct identification of the point on the curve and clarify the relationship between the function and its derivative.

Discussion Status

Participants have engaged in confirming the correctness of the tangent line equation and discussing the specific point of tangency. There is a mix of agreement and clarification regarding the calculations and the interpretation of the tangent line's significance.

Contextual Notes

There is a mention of potential confusion regarding the point of tangency, specifically whether it should be evaluated at the function value or the derivative. The discussion reflects on the importance of accurately identifying the coordinates involved in the tangent line equation.

priscilla89
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Homework Statement



Find an equation of the tangent line to y = sin x at the point x = 0. Graph both functions on the same set of axes on the interval [-pie/4, pie/4]. What does this illustrate?

Homework Equations



y = mx + b

The Attempt at a Solution



y = sin x ---> y' = cos x

y = cos (0) = 1


y = mx + b
0 = 1 (0) + b
0 = b

y = x + 0

I'm wondering if I am on the right track. Any help will be appreciated, thanks a lot.
 
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hi priscilla89! :wink:

yes that's right … the tangent line is y = x :smile:
 


Ok thanks a lot.

- Happy Holidays
 


you meant y=sin(0) right? because the point is (x,f(x)) not (x,f'(x)) but it seems you corrected it when you found the equation of the line so I think it's ok.
 


Right it would've to be y = sin (0) = 0. Basically it would be then

0 = 0 + b

b= 0
 

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