What equations are needed to solve a block in oil puzzle?

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    Block Oil Puzzle
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To solve the block in oil puzzle, the gauge pressure at the upper face of the block can be calculated by determining the pressure from the oil above it, while the pressure at the lower surface accounts for the water below. The relevant equations include the relationship between pressure differences and buoyant force, which is influenced by the densities of both oil and water. The volume of the block is essential for calculating its density, which can be derived from the buoyant force equation. The gauge pressure is defined as the pressure relative to atmospheric pressure, allowing for simplifications in calculations. Understanding these principles is crucial for solving the problem effectively.
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[SOLVED] block in oil

Homework Statement


A cubical block of wood 10.0cm on a side floats at the interface between oil and water with it's lower surface 3.00cm below the interface. The density of the oil is 0.790kg/m^3.
a) what is the gauge pressure at the upper face of the block?
b) what is the gauge pressure on the lower surface of the block?
c) find the density of the block.

http://img156.imageshack.us/img156/6067/81479390rw0.th.jpg


Homework Equations





The Attempt at a Solution



do I use these equations ?
I'm not sure about the volume of the block. If according to the picture (I redrew it), it's 2cm below the interface what would that change?

I thought I would use these equations but not sure after the interface issue arises in this problem

a) B=(P_{bottom}-P_{top})A = \rho g V= mg

I don't have the buoyant force though...and I thought that the Pbottom - Ptop would be the gauge pressure but is this correct?

b) I think that since it is below the interface of the oil then I would take the density of water instead of the oil
B=(P_{bottom}-P_{top})A = \rho g V= mg

c) not sure once again but thinking of using this equation

B-F_g= (\rho _{fluid}- \rho_{object})g V_{object}

However I don't have the mass of the block...hm..

Help please.
could someone tell me if I'm going in the right direction?

Thank you
 
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You do NOT have to consider buoyancy in the force balance because the buoyancy is caused by the pressure on the faces.:)
 
so how would I solve to find the gauge pressure?
 
can someone Please help me out with this problem??
 
The gauge pressure is just the pressure relative to atmospheric pressure.

You need to compute Ptop and Pbottom first, using just how much oil or water is above the depth of the top or the bottom of the block.

For c) you can use the equation you quoted at a). What is the volume of a block with height 10 cm and top area A?
 
kamerling said:
The gauge pressure is just the pressure relative to atmospheric pressure.

so it would be P-P(atmosphere)?
You need to compute Ptop and Pbottom first, using just how much oil or water is above the depth of the top or the bottom of the block.
so would there be 3cm of oil?

For c) you can use the equation you quoted at a). What is the volume of a block with height 10 cm and top area A?

volume of a block?

well it would be 10cm^3
 
You can ignore atmospheric pressure because it gets added to all the pressures, and just treat the experiment as if it's done in vacuum.

There would be 3 cm of oil at the top.

10 cm^3 isn't correct. I asked for the volume with A still in it, because A also appears in
<br /> B=(P_{bottom}-P_{top})A = \rho g V= mg <br />
 
Thanks for your help kamerling
 
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