What Factors Increase the Acceleration on a Spinning Wheel?

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The acceleration of a point on a spinning wheel can be increased by a factor of 4 when the angular velocity is multiplied by 2 and the angular acceleration is multiplied by 4, confirming option E as correct. The discussion highlights the importance of understanding radial and tangential acceleration in circular motion. Participants emphasize the need to work with ratios rather than absolute values when substituting into equations. The correct formula for total acceleration combines both radial and tangential components. Ultimately, the consensus is that option E accurately reflects the conditions for increasing acceleration.
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Homework Statement


The magnitude of the acceleration of a point on a spinning wheel is increased by a factor of 4 if:
A) the magnitues of the angular velocity and the angular acceleration are each multiplied by a factor of 4
B) the magnitues of the angular velocity is multuplied by a factor of 4 and the angular acceleration is not changed
C) the magnitues of the angular velocity and the angular acceleration are each multiplied by a factor of 2
D) the magnitues of the angular velocity is multiplied by a factor of 2 and the angular acceleration is not changed
E) the magnitues of the angular velocity is multiplied by a factor of 2 and the magnitudeof the angular acceleration is multiplied by a factor of 4

answer is E

Homework Equations





The Attempt at a Solution



Okay i tried working back from this and must be doing something wrong,

I start with Aradial = v^2/r = rω^2
and Atangential = rα

I rearange for A = Aradial + Atangentail (as vectors)

which is = r√α^2 + ω^4

subbing in 4 and 2 i get r√32
 
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You have interpreted "acceleration" in the question to mean the total acceleration.
For circular motion, radial acceleration (##\small{\ddot r}##) is zero - so you are summing the tangential and centripetal acceleration.

So ##a=r\sqrt{\omega^4+\alpha^2}##

So far so good - but
subbing in 4 and 2 i get r√32
...what did you put 4 nd 2 into and why?

Consider, multiplying angular velocity by 2 means that where you see a ##\omega## before, you put a ##2\omega##.

Working in reverse is a good idea.
You need to put ##a_{new}=4a=4r\sqrt{\omega^4+\alpha^2}##... work out how that 4 fits against the angular terms.
 
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bennyq said:
Okay i tried working back from this and must be doing something wrong,

I start with Aradial = v^2/r = rω^2
and Atangential = rα

I rearange for A = Aradial + Atangentail (as vectors)

which is = r√α^2 + ω^4

subbing in 4 and 2 i get r√32

|a| = r√(α24) ,Now when you put αnew=4α and ωnew =2ω ,you get r√(16(α24)) = 4r√(α24)

Hence option E is correct.
 
ohhh of course.. thanks
 
I think your mistake is that you are substituting values when you should be substituting in ratios.
 
FINAL (I hope) EDIT:

I agree it's E.
 
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