What Factors Influence Acceleration in Non-Uniform Circular Motion?

AI Thread Summary
The discussion revolves around a physics problem involving a car moving in non-uniform circular motion on a track with radius r and tangential acceleration a_{lin}. The user calculates the tangential speed after one lap as v_{lap} = 2√(π a_{lin} r) and expresses the car's acceleration as a_{car} = -4π a_{lin}âˆhat{r} + a_{lin}âˆhat{v}. They express confusion about the relationship between the car's acceleration and the radius of the track, questioning why the acceleration does not seem to depend on r. Additionally, they ponder the implications of taking the limit as r approaches infinity, speculating about the behavior of speed and centripetal acceleration in that scenario. The user seeks clarification on these concepts and their interpretations.
MasterTinker
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I know this problem looks easy but my physics mind is out of shape.

Problem

Imagine that you have a car traveling along a circular, horizontal track or radius r, with tangential acceleration a_{lin}. If the car begins moving around the track with velocity 0 m/s:

1. What is the tangential speed of the car after one lap?

2. What is the acceleration of the car after it completes one lap?

3. What is the \displaystyle\lim_{r\rightarrow\infty} of the answer in 2?

Attempt at a Solution

1.

In order to calculate the tangential speed of the car after one lap, v_{lap}, I first calculate the time it would take for it to complete a lap. The distance around the track is 2\pi r, and using a kinematics equation:

2\pi r=\frac{1}{2}a_{lin}t^2

t=2\sqrt{\frac{\pi r}{a_{lin}}}

v_{lap} is just acceleration by time, therefore:

v_{lap}=a_{lin}t

v_{lap}=a_{lin}\left(2\sqrt{\frac{\pi r}{a_{lin}}}\right)

v_{lap}=2\sqrt{\pi a_{lin}r}

2.

If I define \hat{r} to be the unit vector pointing directly outwards from the center of the circle, and \hat{v} to be the unit vector pointing in the direction of the car's tangential motion, then the acceleration of the car, a_{car}, is:

a_{car}=-a_{centripetal}\hat{r}+a_{tangential}\hat{v}

The centripetal acceleration is proportional to the car's velocity and the radius of the track, while the tangential acceration is just a_{lin}, therefore:

a_{car}=-\frac{v_{lap}^2}{r}\hat{r}+a_{lin}\hat{v}

a_{car}=-\frac{\left(2\sqrt{\pi a_{lin}r}\right)^2}{r}\hat{r}+a_{lin}\hat{v}

a_{car}=-4\pi a_{lin}\hat{r}+a_{lin}\hat{v}

3.

Uh-oh

What's Wrong?

I don't see any problem with the way I derived the velocity of the car after one lap. I think how I did the car's acceleration is okay, but what I don't understand is that it is not based on the radius of the track (does this seem weird to anyone else?) and I can't figure out how to interpret the limit required in part 3.

What I would think is that as r approaches \infty the car will have an infinite speed by the time it completes a lap, and therefore have an infinite centripetal acceleration. Or would the car not be able to complete a lap? Or would the centripetal acceleration be 0 as a circle of infinite radius becomes a line? I really don't know what to think, please help me interpret this problem.
 
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By the way I apologize for not placing this in the homework forum. If it's crowding then please redirect it there : )
 
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