What Force is Needed to Reach a New Position in Physics?

  • Thread starter Thread starter sheers
  • Start date Start date
  • Tags Tags
    Force Motion
sheers
Messages
1
Reaction score
0
A 2.50kg object is moving along the x-axis at 160m/s. as it passes the origin, two forces F1 and F2 are applied, both in the y direction f1=15N in the j direction. The forces are applied for 3.00s after which the object is at the point x=4.80m y=10.8m. Find f2.

can anyone figure out how to do this?
 
Physics news on Phys.org
Welcome to PF!

Hi sheers! Welcome to PF! :smile:
sheers said:
A 2.50kg object is moving along the x-axis at 160m/s. as it passes the origin, two forces F1 and F2 are applied, both in the y direction f1=15N in the j direction. The forces are applied for 3.00s after which the object is at the point x=4.80m y=10.8m. Find f2.

can anyone figure out how to do this?

yes, you can :wink:

use good ol' Newton's second law (F = ma), and the standard constant acceleration equations …

what do you get? :smile:
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top