What happens after an electron is excited by a photon?

In summary, when an electron is excited by a photon, it absorbs the energy from the photon and jumps to a higher energy level. This causes the electron to become unstable and it quickly returns to its original energy level, releasing the absorbed energy in the form of a photon. This process is known as emission and is the basis of many light-based technologies, such as lasers and LEDs. Additionally, the specific amount of energy absorbed by the electron determines the color of the emitted photon, allowing for a wide range of colors to be produced.
  • #1
Voltz
21
0
I understand the concept of an electron being raised from it's ground state by a photon with the correct wavelength, but then what? I ask because if the electron remained in it's excited state then surely shining a bright light on a material for long enough would 'saturate' it's electrons and cause it to become transparent to a given wavelength. But then if the electrons fall from their excited state then surely the energy of the photon, need to be conserved, is re-emitted by the material?

Also if electrons can only absorb wavelengths of light at exact frequencies to promote them then why are the majority of materials opaque to so many frequencies of the visible spectrum?
 
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  • #2
But then if the electrons fall from their excited state then surely the energy of the photon, need to be conserved, is re-emitted by the material?
This is one option. The other options would be to produce some heat, to excite other electrons and probably something I forgot.

Also if electrons can only absorb wavelengths of light at exact frequencies
They always have a natural width of the transition and a doppler broadening due to their temperature. However, this is not relevant here. If the electron can reach a free band (in metals or semiconductors), you get a full range of possible energies. In other materials, you can have other allowed transitions between energy levels in the material.
 
  • #3
mfb said:
This is one option. The other options would be to produce some heat, to excite other electrons and probably something I forgot.

What is the mechanism by which the electrons heat up?

mfb said:
They always have a natural width of the transition and a doppler broadening due to their temperature.

Does this mean that transparencies would change at much lower temperatures, e.g. the ground state of electrons at 0K?

mfb said:
In other materials, you can have other allowed transitions between energy levels in the material.

Wouldn't this cause absorptions at specific frequencies such as that exhibited by interstellar gases, I still don't understand how one material can absorb such a wide band of photon wavelengths
 
  • #4
Not the electrons, the material can heat up, which corresponds to atoms and sometimes electrons moving around.

Does this mean that transparencies would change at much lower temperatures, e.g. the ground state of electrons at 0K?
In some situations, the absorption coefficient for a specific wavelength can depend on the temperature, right.

I still don't understand how one material can absorb such a wide band of photon wavelengths
Let's take a metal, as it is quite easy to understand there:
You have some electrons which are bound to specific atoms, they are not relevant here.
In addition, you have some electrons which are not bound to specific atoms. They are similar to free charges in a very large box, and therefore the allowed energy levels are extremely dense. For every photon in a wide energy range (especially all photons of visible light), every charge can absorb it and go to a higher energy level.
 
  • #5
mfb said:
Let's take a metal, as it is quite easy to understand there:
You have some electrons which are bound to specific atoms, they are not relevant here.
In addition, you have some electrons which are not bound to specific atoms. They are similar to free charges in a very large box, and therefore the allowed energy levels are extremely dense. For every photon in a wide energy range (especially all photons of visible light), every charge can absorb it and go to a higher energy level.

In the case of a metal if the electrons are delocalized then how can they be promoted?
 
  • #6
Voltz said:
In the case of a metal if the electrons are delocalized then how can they be promoted?

Delocalized just means that the orbital of the electron isn't around just one atom, but around multiple. See here: http://en.wikipedia.org/wiki/Delocalized_electron
 
  • #7
Ok then, how does the electron cause a heating of the atom through it's excitation? And does this mean that much of light energy falling on a surface is turned into heat or is it just a nominal amount. And can any wavelength cause a heating effect - e.g. a focused gamma ray burst will cause extreme heating?
 

1. What does it mean for an electron to be excited by a photon?

When an electron is excited by a photon, it means that the electron absorbs the energy from the photon and jumps to a higher energy level. This is known as an excited state.

2. What happens to an excited electron?

An excited electron will eventually return to its original energy level, releasing the absorbed energy in the form of a photon. This process is known as emission or deexcitation.

3. How does an electron become excited by a photon?

An electron can become excited by a photon when the photon's energy matches the energy difference between the electron's current energy level and a higher energy level. This is known as the absorption of a photon.

4. What determines the energy level an electron will jump to after being excited by a photon?

The energy level an electron jumps to after being excited by a photon is determined by the difference in energy levels between the electron's current state and the higher energy state. This is based on the amount of energy carried by the photon.

5. Can an electron be excited by multiple photons?

Yes, an electron can be excited by multiple photons if their combined energy is enough to reach a higher energy level. This is known as multi-photon excitation and is commonly observed in high-energy laser experiments.

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