What Happens When Superheated Water Meets a Nucleation Site?

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When superheated water at 103°C is introduced to a nucleation site, energy is released, calculated using the heat capacity of water. The energy released is approximately 12.552 J/g, or 2675.2 kJ/kg when considering the enthalpy and pressure. To determine the volume of steam produced, the mass of water is converted to moles, with 1 mole of gas occupying 22.4 liters. Alternatively, using steam tables can provide the specific volume for steam at 1 atm and 103°C. The discussion emphasizes the importance of understanding thermodynamic principles in calculating energy release and steam volume.
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Homework Statement


1 Liter of water is microwaved to 103 Celcius at 1atm atmospheric pressure.
1)How much energy is released when you add a nucleation site to the container to release steam?Heat capacity of liquid water is 4.184 J/K*g
2)Ignoring surface tension, how much steam in mL could be produced given the latent heat of boiling water is 2260 J/g?


Homework Equations


H=U+PV
U=[Cv]Delta[T]


The Attempt at a Solution



U=[Cv]Delta[T]
U=(4.184 J/K*g)(3 K)
U=12.552 J/g

or

U=H-PV H(.1 MPa, 103 C)=2676.2 kJ/kg
U=(2676.2)-(.1 MPa)([10 [m]^{3}) steam tables and converting atm to MPa
U=2675.2 kJ/kg


As far as part 2 goes, I really need some help.
 
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Convert the liter of water to a mass and determine the number of moles. One can find the volume of steam using the ideal gas - 1 mole of gas occupies 22.4 l of volume.

Otherwise use a steam table and select the appropriate specific volume for steam at 1 atm and 103C (slightly superheated), and multiply by the mass.
 

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