What influences the binding energy of nucleons in a nucleus?

AI Thread Summary
The discussion focuses on the binding energy of nucleons in a nucleus, specifically how it is influenced by the strong interaction, which does not differentiate between protons and neutrons and acts as a contact force. Participants explore the relationship expressed by the equation U_f = E_f A^r Z^p, aiming to determine the values of r and p. Through analysis, it is suggested that if the number of nucleons (N) is constant while varying the number of protons (Z), the energy per nucleus remains consistent without long-range contributions. A key conclusion is that the binding energy is primarily affected by the immediate interactions of nucleons surrounding each other. The conversation emphasizes the importance of understanding these interactions to derive the constants r and p accurately.
Bestfrog

Homework Statement


The component of nucleus' energy due to the strong interaction (with ##Z,A >>1##) can be written as ##U_f = E_f A^r Z^p##, (##E_f## is a constant with the dimension of a energy). Find ##r,p## knowing that
(i) strong interaction doesn't distinguish between protons and neutrons
(ii) strong interaction is a force of contact
Can you give me a hint to start?
 
Physics news on Phys.org
Did you try different values and see if they fit to the constraints?

In particular, what happens if you keep A constant and change Z?

What can you say about the energy per nucleus if there is no long-range contribution?
 
I don't know how to use the constraints, maybe I miss some theory..
 
See the two hints I gave.
 
mfb said:
See the two hints I gave.
I have an idea. If ##N## is the number of neutrons, then ##U_f = E_f (Z+N)^r Z^p##. For the constraint (i) if I first put ##Z=1## and so ##N=1##, then I put ##Z=2## with ##Z+N## constant (N=0), I have $$E_f 2^r \cdot 1 = E_f 2^r 2^p$$ so ##p=0##.
 
mfb said:
What can you say about the energy per nucleus if there is no long-range contribution?
Can you explain this in other words? I don't get what you say
 
If nucleons are only influenced by nucleons directly around them, and every nucleon always has nucleons directly around it, what can influence the binding energy for this particular nucleon?
 
Back
Top