What Initial Velocity Ensures a Glass Slides Off a Table with Coulomb Friction?

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Homework Help Overview

The problem involves a glass sliding on a table and seeks to determine the initial velocities that would cause the glass to fall off the table, considering only Coulomb friction as the acting force.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants discuss the relationship between initial velocity and the forces acting on the glass, particularly questioning the role of the initial push versus friction. There is an exploration of the differential equations that could describe the motion.

Discussion Status

Some participants have provided insights into the nature of the forces involved and the equations that may apply. There is an ongoing debate about the definitions and implications of the forces at play, particularly regarding the characterization of friction.

Contextual Notes

Participants note confusion regarding the definitions of friction forces, with references to different types of friction and their mathematical representations. There is an acknowledgment of varying interpretations of the problem's constraints.

kristiakemi
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Homework Statement


Consider a glass of mass m starting at x=0 and sliding on a table of LENGTH H. For what initial velocites V(naught) will the glass fall off the table if the only force is Coulomb friction?


Homework Equations


Fcoulomb = -c(dx/dt) where c >0 and is defined as the friction coefficient.


The Attempt at a Solution



I assumed that we need to find the min initial velocity such that the glass just barely falls off. Thus the initital velocitIES will be all those values greater than V(naught). Sum of the Forces in the x direction are : coulomb friction + F(the initial push). Can I solve this system by saying m*d^2x/dt^2) -c(dx/dt) = 0 with differential equations?

Thanks!
 
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Yes, one of the solutions is [itex]c_{1}[/itex], and the other is [itex]c_{2} e^{\frac{c}{m}t}[/itex]

Why do you have F(initial push)? even thought you didn't use it, the problem states only one force acting on the glass.
 
Last edited:
I think this is where I'm confused: the problem says the only force acting on it is from friction but there must be another force acting on it in the x direction in order for it to begin moving, right? Since the friction is working against the motion, I know that the F(friction)<Fpush...if there is a push?
 
You don't care about what gave the glass the magnitude of [itex]v(0)[/itex], what you care is to which value of the initial speed, the glass will fall off the table.

Now set the ODE for the v case, too.
 
By the way, i dosed for a moment, but cv is not Coulomb's friction.
 
its not? Thats how its defined in my book...it says exactly:

F(friction) = -c(dx/dt) where c is a positive constant (c>0) referred to as the friction coefficient. This force-velocity relationship is called a linear damping force. We can assume that the frictional force is linearly dependent on the velocity. In later sections, exercises will discuss the mathematical solution of problems involving this type of friction, called coulomb friction.

is there another equation that i should know?
 
kristiakemi said:
its not? Thats how its defined in my book...it says exactly:

F(friction) = -c(dx/dt) where c is a positive constant (c>0) referred to as the friction coefficient. This force-velocity relationship is called a linear damping force. We can assume that the frictional force is linearly dependent on the velocity. In later sections, exercises will discuss the mathematical solution of problems involving this type of friction, called coulomb friction.

is there another equation that i should know?

As far as i know, that's the viscous force (drag for laminar flows). Anyway, since I'm only familiar Coulomb friction (dependent on forces rather than velocity) in the "dry sense" i am not going to argue the book, but it looks odd to me. I'll let this argument rest for other members.
 

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