What is fluorescence and how does it arise?

  • Thread starter Thread starter retupmoc
  • Start date Start date
  • Tags Tags
    Fluorescence
AI Thread Summary
Fluorescence occurs when a molecule absorbs light at one energy level and subsequently emits light at a lower energy level. This process begins with an electron being excited to a higher-energy orbital after absorbing a photon. The molecule's nuclei then slowly rearrange to a more favorable configuration, resulting in a slight decrease in energy. When the electron returns to its ground state, it emits a photon with energy that reflects this change, which is lower than the energy of the absorbed photon due to the energy lost during nuclear relaxation. Understanding these mechanisms is crucial for answering related exam questions effectively.
retupmoc
Messages
47
Reaction score
0
What is fluorescence and how does it arise?

Is it just a spontneous de-excitation after the electron in the molecule (protein) has been excited. This is a 6 mark question in last years Chemistry-2 exam and i don't really know how to go about answering it. Any suggestions?
 
Physics news on Phys.org
At http://www.Newton.dep.anl.gov/askasci/phy99/phy99540.htm
it says:
Question - What is flourescence? How does it work? ----------------- Fluorescence is when a molecule absorbs light of one energy and later emits light of a lower energy. Briefly, what happens is that upon absorption of the first photon, an electron is promoted to a higher-energy orbital. This raises the energy of the molecule by an amount equal to the energy of the photon absorbed.
Electrons move very fast, as they are much lighter (factors over 1000) than
atomic nuclei. When the electron is in its new higher-energy state, the
most favorable arrangement of the nuclei changes a little. Because the
nuclei are so heavy, they will (comparatively) slowly reorganize to their
most favorable arrangement. This lowers the total energy of the molecule.
It is still higher than in the ground state, but not as much higher as the
energy of the absorbed photon.

Eventually, the promoted electron will drop back down to its ground-state
orbital. In doing so, a photon of light is emitted, with an energy equal to
the change in energy of the molecule. Recall that the molecule's atomic
nuclei are no longer in their ground-state geometry, so its new energy is a
bit higher than in the original ground state. So, the energy of the emitted
photon will be less than the energy of the absorbed photon because of the
energy cost of relaxation of the nuclei, both before and after emission of
the second photon.
 
thanks for the help
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top