What is happening in my circuit?

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When a solid signal is applied to the base of an NPN transistor, it allows collector current to flow, effectively saturating the transistor and enabling it to act as a switch. This saturation results in a low voltage between the emitter and collector, allowing current to flow through the relay, which activates it. The relay turning on indicates that current is indeed flowing through the transistor, which generates a magnetic field necessary for the relay's operation. If a faulty transistor short-circuits the collector and emitter, the relay may still activate, but it would remain on without base current. Understanding the relationship between base current and collector current, influenced by the transistor's gain (hFE), is crucial for circuit functionality.
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If I have a relay coil hooked up to the collector port of a transistor and have a solid signal going in the base, can somebody explain what is happening inside the transistor right when the relay turns on? (npn transistor)
 
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The transistor is being given base current, so it causes collector current to flow. The circuit is designed so that the base current is greater than the minimum needed to cause this particular collector current, so the transistor saturates (has a very low voltage between E and C) and acts like a good switch. The collector current is the current in the relay.
 
the relay turning on is really just a signal that current is flowing between the collecter and emitter?
 
should be like that as current flow creates a mag field in the relay and turns it on (atleast most of them work that way)

Just like Nascent said , when a BJT gets a high enough base current the C E junction conducts or is open so current flows from the source you have through the relay then through the transistor to whatever is next there in your circuit.
 
Crazymechanic said:
should be like that as current flow creates a mag field in the relay and turns it on (atleast most of them work that way)

Just like Nascent said , when a BJT gets a high enough base current the C E junction conducts or is [strike]open[/color][/strike] closed[/color] so current flows from the source you have through the relay then through the transistor to whatever is next there in your circuit.
I recall someone being taken to task ( in a most civil PF way, of course, :smile: ) previously over the OPEN and CLOSED convention for switches. That wasn't you, Crazy, was it? :wink:
 
PsychonautQQ said:
the relay turning on is really just a signal that current is flowing between the collecter and emitter?

"Just a signal" isn't the best way to describe it. The current is necessary to turn the relay on.

If the circuit is working correctly then yes the relay turning on is evidence that current is flowing through the transistor.

But consider what happens if I replace your transistor with one that is faulty and has a short circuit between the collector and the emitter. The relay would still turn on. Of course it would also stay on even when there was no current going into the base of the transistor.
 
what is happening inside the transistor

There are a lot of web sites with explanations of how a NPN transistor works. Most are quite complicated and assume you understand how a diode works. Is that the problem? Do you need a simpler explanation?

Basically if your circuit pushes ?mA into the base of an NPN then upto hFE * ?mA can flow from collector to emitter. hFE is the gain of the transistor and is typically around 60-200 for common transistors. Let's assume the gain of your transistor is 100.

So if your base current were say 2mA then the transistor will allow upto 2 * 100mA = 200mA to flow between collector and emitter.

I say "upto" because the actual current in your circuit might be limited by the resistance of the relay coil. If the supply voltage was 12V and the relay coil 1k Ohms then only about 12mA will flow when the transistor is on/conducting.
 

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