The strong force which is binding in nuclei is symmetric under the exchange neutron <-> proton (or down <-> up). There are other forces, for instance the electromagnetic repulsion between two protons, which are not binding and not symmetric. As the name suggests, the non-symmetric part is only a perturbation. So, using the asymmetry parameter
[tex]\alpha = \frac{N-Z}{A}[/tex]
and the density [itex]\rho[/itex], we develop the energy density in the nuclear medium [itex]E(\rho,\alpha)[/itex] as a Taylor series
[tex]E(\rho,\alpha) = E(\rho,0) + S(\rho)\alpha^2 + O(\alpha^4) + \cdots[/tex]
and expanding around the saturation density [itex]\rho_s[/itex]
[tex]S(\rho) = \left.\frac{1}{2}\frac{\partial^2 E}{\partial\alpha^2}\right|_{\alpha=0,\rho=\rho_s}=a_v+\frac{p_0}{\rho_s^2}(\rho-\rho_s)+\cdots[/tex]
The symmetry energy [itex]a_v\approx 29 \pm 2[/itex] MeV
source :
The nuclear symmetry energy