What is present during the following times of the Dumas procedure

  • Thread starter Thread starter Zoey Brown
  • Start date Start date
  • Tags Tags
    Procedure
AI Thread Summary
During the Dumas procedure with methanol, after the methanol is added and the flask is covered with foil, the contents include liquid methanol (l) and air (g). Just before removing the flask from the hot water bath, the methanol is present as a gas (g) due to vaporization, with air expelled from the flask. The discussion highlights the importance of understanding the phase changes of methanol throughout the procedure. Participants express uncertainty about the final state of the flask's contents after cooling, indicating a need for clarity on the process. Overall, the Dumas procedure involves careful observation of the states of methanol and air at different stages.
Zoey Brown
Messages
17
Reaction score
0
Moved from a technical forum, so homework template missing
From the list below, identiyfy what is present in the flask at each of the following times during the Dumas procedure performed with methanol:
Methanol (g)
Methanol (l)
Methanol (aq)
Air (g)
Water (l)
Water (g)

a) After the methanol is added and the flask is covered with foil?
b) Just before the flask is removed from the hot water bath?
c) When the flask is weighted after cooling?

My solution:
a) i think this would be methanol (l) and air (g) bc there is no evidence that methanol is in aq form
b) i think this would be methanol (g) bc all the air is expelled and the methanol is vapourized
c) this one i have no clue and don't even know how to reason out!
 
Physics news on Phys.org
a and b seem to me OK.

Dumas, Dumas, it rang a bell. I'm sure we did something, calculations, maybe experiments and calculations at school, so I now look up what it was, there is some practically washed out memories somewhere there.*

Anyway the Wiki description says "The vessel is then heated in a boiling water bath; all the air within the flask would be expelled, replaced by the vapor of the unknown substance" and then the flask is a sealed. So that appears to me quite a clue - does that suggest to you how to reason out, and if you have any doubts what are they? You are unfortunately not doing the experiment, but imagine you are doing it, and thinking of what purpose you’re doing it for.

*" culture is what remains when you have forgotten everything you ever learned"
 
Last edited:
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...
Back
Top