What Is Tarzan's Maximum Tolerable Speed When Swinging on a Vine?

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Tarzan's maximum tolerable speed while swinging on a vine can be calculated using the forces acting on him at the lowest point of his swing. With a mass of 70 kg and a maximum pulling force of 2000 N, the centripetal force required for circular motion is provided by this force. The relationship between centripetal force, mass, and speed is crucial for determining his maximum speed. Understanding how centripetal acceleration relates to speed will help in solving the problem. The discussion emphasizes the need for applying Newton's laws to find the solution.
jordanb23
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i have one question that i need help on

Tarzan plans to cross a gorge by swinging in an arc from a hanging vine (Fig. 5-41). If his arms are capable of exerting a force of 2000 N on the rope, what is the maximum speed he can tolerate at the lowest point of his swing? His mass is 70 kg and the vine is 4.8 m long.

i diont know how to start and what formulas to use
can someone please help me
 
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Welcome to PhysicsForums Jordan. Hope we can help you with some of your physics problems.

Tarzan will swing along a circular path if he hangs onto the vine. His speed will increase towards the bottom and will be a maximum at the lowest point. Motion in a circle requires that a centripetal force be exerted on Tarzan. Now according to Newton's third law if he exerts a 2000 N pulling force on the vine (he needs to pull himself up on the vine) the vine will exert a force of similar magnitude on him. This force is the centripetal force that will help him to swing along a circular path. Do you now how the centripetal force will be related to his speed? Or his centripetal acceleration?
 

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