What is the acceleration of m2 in a frictional pulley system?

AI Thread Summary
In a frictional pulley system, mass m1 (34.3 kg) is on a horizontal surface and connected to mass m2 (5.30 kg) via a string. A force of 201.7 N acts on m1 at a 32.1-degree angle, with a coefficient of kinetic friction of 0.185 between m1 and the surface. The equations for horizontal force, friction, and tension are used to determine the upward acceleration of m2. The solution involves calculating the net forces acting on both masses to find the acceleration. The discussion highlights the importance of correctly applying Newton's laws and friction concepts in this scenario.
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Homework Statement



Mass m1=34.3 kg is on a horizontal surface, connected to mass m2= 5.30 kg by a light string as shown. The pulley has negligible mass and no friction. A force of 201.7 N acts on m1 at an angle of 32.1o.
The coefficient of kinetic friction between m1 and the surface is 0.185. Determine the upward acceleration of m2.

Homework Equations



F_given * cos(theta) = F_Horizontal
F_friction = mgμ_k
F_horizontal - F_friction - T = m_1 * a
T = m_2 * a + m_2 * 9.81

The Attempt at a Solution


F_horizontal - F_friction - m_2 * 9.81 = m_1 * a + m_2 * a
 
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qi0n said:

Homework Statement



Mass m1=34.3 kg is on a horizontal surface, connected to mass m2= 5.30 kg by a light string as shown.

Nothing is shown!

ehild
 

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