What is the actual equation of e=mc^2?

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The discussion centers on the equation E=mc², which is a simplified version of the more complex equation E² = p²c² + m²c⁴. Participants clarify that "p" represents momentum and debate the perspectives of massists and energists regarding mass and energy attribution in different states of motion. Massists attribute mass values to objects regardless of their motion, while energists focus on energy values, leading to different interpretations of the equations. The conversation highlights that modern physicists tend to lean towards the energist viewpoint, particularly in high-energy physics. Ultimately, the discussion emphasizes the nuanced understanding of mass and energy relationships in physics.
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what is the actual equation of e=mc^2? this is only the simplified equation, and i have forgotten the actual one already...
 
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You probably mean

E2 = p2c2 + m2c4

- Warren
 
what does the P stand for? and is that equation homogenous?
 
It's a lowercase p, and it stands for (linear) momentum. I don't know what you mean by "homogenous."

- Warren
 
It all depends on whether you are a massist or an energist.

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A massist is willing to attribute mass values to anything, in any state of motion. For a massist, this m is really m0, a mass attributed to something in its rest frame of reference. For a massist

E2 = p2c2 + m02c4
p = mv

are always true in any inertial frame. For light quanta,

E = pc
p = mc

, because m0 = 0 for light quanta. But m = p/c = E/c2, a mass value dependent upon total energy of a quantum.
So E = mc2 is true for a light quantum as well as a particle with a non-zero rest mass.

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An energist is willing to attribute energy values to anything, in any state of motion. For an energist, m can only be attributed to something in its rest frame, so the subscript 0 is never needed. For an energist,

p2 = E2/c2 - m2c2

is always true in any inertial frame. The energy E must come from other physics. For light quanta, p = E/c is a given, so

p2 = p2 - m2c2

, so

m2c2 = 0

. Since c > 0,

m = 0 for a light quantum.
So, E = mc2/(1 - v2/c2)1/2 only in the case of a particle with non-zero rest mass.

------

Most modern day physicists, especially high-energy physicists, tend to be energists rather than massists.
 
I said:

So, E = mc2/(1 - v2/c2)1/2 only in the case of a particle with non-zero rest mass.

I should have said:

So, E = mc2/(1 - v2/c2)1/2 only in the case of a particle with non-zero mass.
 


Originally posted by alchemist
what is the actual equation of e=mc^2? this is only the simplified equation, and i have forgotten the actual one already...

The equation E = mc2 is the mass-energy equation relating the mass m of a particle to the free-particle energy E. The proof can be found here

www.geocities.com/physics_world/sr/mass_energy_equiv.htm

If the particle is a tardyon (i.e. a particle which travels at speeds less than light) then

m = m0/sqrt[1-(v/c)2]

Multiply both sides by c2

mc2 = m0c2/sqrt[1-(v/c)2]

Substitute in E = mc2 to get

E = m0c2/sqrt[1-(v/c)2]

This equation can be rewritten as

E2 - (pc)2 = (m0c2)2

Pete
 

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