What Is the Allowable Signal Swing in a BJT?

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The discussion focuses on understanding the allowable signal swing in a BJT circuit with specified voltage and current values. The circuit parameters include V(cc) = 10 V, V(ee) = -10 V, and a current gain (B) of 100. The calculated allowable signal swing is +8 V and -3.4 V, with confusion arising around the meaning of -3.4 V. Participants clarify that B represents the transistor's beta, and the values can be used to determine input peak-to-peak voltage and current. The conversation emphasizes the need for clarity in interpreting textbook examples related to BJT operation.
Peon666
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I'm utterly confused about this concept and the textbook quite efficiently confuses me further. I'll just try to explain it with an example:

The circuit has a V(cc) = 10 V and V(ee) = -10 V. V(c) = 2 V, V(e) = -1.7 V, V(b) = -1 V, I(c) = 1 mA, I(e) = 1 mA.

It says that allowable signal swing or B=100 is +8 V, -3.4 V.

How's that? I can't figure.
 
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If this is a homework problem, it should go there. What is the book asking for, the input peak to peak input voltage?

The only thing I don't understand is what is the -3.4 V. B = 100 is probably referring to the beta or current gain of the transistor. The 8 V seems like a reasonable value for the output signal voltage swing. From the other data given it is possible to calculate the input peak to peak current and peak to peak voltage.

What exactly is confusing you?
 
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