What is the angle of the rope in Physics 11 problem 10?

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To find the angle of the rope in the physics problem, the equation W = Cos(theta) * F * d is used, where W is the work done, F is the force applied, and d is the distance. Given the values of W (1.20 x 10^4 J), F (125 N), and d (185 m), the angle can be calculated using theta = arccos(W / (F * d)). The discussion confirms that the correct angle is not 1.0 degrees, prompting further clarification on the calculation process. Participants emphasize the importance of correctly applying the formula to determine the angle accurately. The conversation highlights the need for detailed steps in solving physics problems involving angles.
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Homework Statement


An 845N sled is is pulled a distance of 185m. The taskt requires 1.20 x 10^4J of work and is done by pulling a rope with a force of 125N. At what angle is the rope held


Homework Equations


W=Cos(of theta) Fd


The Attempt at a Solution


F=845N
d=185m
W=1.20x10^4J
F=125N
angle=?

I know how to do this question if I am given an angle but i don't really know what to do when I am supposed to be finding the angle.
 
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theta = arccos(W/(F*d)) is how you'd find the angle given that eqn.
 
is the right answer 1.0 degrees?
 
Iceclover said:
is the right answer 1.0 degrees?
No. You were given the correct equation , please show how you arrived at your answer.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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