What is the Antiderivative of Inverse Sine of x?

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Homework Statement



Find the antiderivative of \frac{1}{\sin\alpha}

Homework Equations





The Attempt at a Solution


Ugh, maybe it's just a temporary brainfreeze, but I have no idea how to go about it.
 
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Try rewriting the sine in terms of exponential functions. After a change of variables and partial fractions you should be able to integrate it.
 
kristo said:

Homework Statement



Find the antiderivative of \frac{1}{\sin\alpha}

Homework Equations





The Attempt at a Solution


Ugh, maybe it's just a temporary brainfreeze, but I have no idea how to go about it.

Maybe if you write that as {\csc\alpha} it will look more familiar.
 
\frac{1}{\sin x} = \frac{\sin x}{1-\cos^2 x}

is a useful thing to know.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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