- #1
steel1
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Homework Statement
Find the area of the region that lies inside the curve r^2=8cos(2θ) and outside r=2
Homework Equations
area of polar curves = .5∫R^2(outside)-r^2(inside) dθ
The Attempt at a Solution
r^2=8cos(2θ) and r=2, so...
4=8cos(2θ)
.5=cos(2θ) since .5 is positive, we need the angles in the first and fourth quadrant
2θ=∏/3 and -∏/3
θ=∏/6 and -∏/6
.5∫8cos(2θ)-4 from -pi/6 to pi/6
=difference of .5[4sin(2θ)-4θ] evaluated at pi/6 and -pi/6. but when i plug the values in, i can't seem to get the right answer