What is the Atomic Force Constant in a Metal Bar Under Tension?

AI Thread Summary
The discussion focuses on calculating the atomic force constant k for a metal bar under tension, using parameters such as length L, cross-sectional area A, Young's modulus E, and atomic separation x. Key steps include deriving expressions for the number of atomic chains, the number of atoms in a chain, the microscopic extension Δx, and the tensile force f between atoms. The relationship f = kΔx leads to the conclusion that k = Ex, with a specific calculation for k given E = 1.2 GN/m² and x = 0.16 nm. Additionally, there is confusion regarding the derivation of expressions and the application of different moduli of elasticity in tension versus compression. Understanding these concepts is crucial for applying finite element modeling effectively.
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Homework Statement



Consider a metal bar of length L, cross-sectional area A, equilibrium atomic separation x, and Young's modulus E. When a tension force F is applied to the bar, it causes an extension ΔL. Calculate the atomic force constant k by deriving expressions for (a) the number of chains of atoms in any cross section, (b) the number of atoms in a single chain of length L, (c) the microscopic extension Δx between atoms, and (d) the tensile force f between atoms. (e) Write f= kΔx and show that k=Ex. (f) Calculate the value of k for a typical metal for which E = 1.2 GN/m^{2} and x=0.16 nm.

Homework Equations



f=kΔx

k=Ex

stress = modulus x strain

F/A = E ΔL/L

ΔL= FL/(EA)



The Attempt at a Solution



Part f is probably the only part of the problem I feel confident about doing. As far parts a through e, I can't make heads or tails of how to derive the expressions involving atomic separation x. This problem seems to somewhat relate Hooke's law with elastic materials and a picture on my book describes the interatomic forces in the material as spring-like.
 
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